I made 4 jump and traced the 4 packets.
-> coordinate of jump & HEX values :
218.253 DA.FD
223 251 DF.FB
213.241 D5.F1
203.243 CB.F3
now the packets :
1c 00 f2 03 4b 4e 88 07 a6 81 19 00 da 00 fd 00 00 00 00 00 df 00 fb 00 8e 00 00 00
1c 00 f2 03 f9 a6 88 07 a6 81 19 00 df 00 fb 00 00 00 00 00 d5 00 f1 00 8e 00 00 00
1c 00 f2 03 ed dc 88 07 a6 81 19 00 d5 00 f1 00 00 00 00 00 cb 00 f3 00 8e 00 00 00
1c 00 f2 03 79 11 89 07 a6 81 19 00 cb 00 f3 00 00 00 00 00 c1 00 f4 00 8e 00 00 00
coordinates are at byte 12+13 & 14+15
1st jump = X:218 Y:253 = in HEX = X:00DA Y:00FD
1c 00 f2 03 4b 4e 88 07 a6 81 19 00
da 00 fd 00 00 00 00 00 df 00 fb 00 8e 00 00 00
Remember to invert bytes (BTW Thx to chocoman4k who posted good info there :

)
I also found that :
byte 0 & 1 = packet length (28 here)
byte 2 & 3 = Packet type (I dont know yet how many type)
byte 4 to 7 = seem to be locked on time (=126373451, 126396153, 126409965, 126423417 for the 4 jumps)
byte 8 to 11 = I'am not sure, but look like to be for the MAP
For all type of packet, byte 0 to 11 seem to respect the same structure.
I'am just starting to understand how they are structured, and wanted to share what I found out.
If someone more advanced in CO packet structure found some mistakes here, I'll be glad to be corrected.