You can get the exp needed for each level by reading 32bit low endians from LevelExp.dat
Code:
'VB
Sub ReadLevelExpDat()
Dim ExpForLevel As Long
datFile = "C:Program FilesConquer 1.0iniLevelExp.Dat"
iniFile = "C:Program FilesConquer 1.0iniLevelExp.txt"
Open datFile For Binary As #1
Open iniFile For Output As #2
For Index = 1 To (LOF(1) - 3) Step 4
Get #1, Index, ExpForLevel
Print #2, ((Index - 1) / 4) + 1 & ": " & Format(ExpForLevel / -1, "###,###,###,##0")
Next Index
Close #1
Close #2
End Sub
I believe that as well, but he only asked for the file that contained the required experience for each lvl - which is what I gave him. It was never updated when levels higher than 130 were released so the client must use a different method within itself to calculate the experience required for them.
I do however have level 130:
Code:
130,8589091472
I believe that is correct, from what I calculated at least. If anyone would like to test it with their 130 character, feel free to do so, worked perfectly for me.
I believe that as well, but he only asked for the file that contained the required experience for each lvl - which is what I gave him. It was never updated when levels higher than 130 were released so the client must use a different method within itself to calculate the experience required for them.
I do however have level 130:
Code:
130,8589091472
I believe that is correct, from what I calculated at least. If anyone would like to test it with their 130 character, feel free to do so, worked perfectly for me.
tyvm
this is the same old one as i had decrypted in the past though :/
i guess they never updated it client side...
[Request/Help] 4267 ItemType Decrypted 12/02/2009 - CO2 Private Server - 9 Replies Hi all!
i need help in how to decrypt or if someone can decrypt it for me please...
Obs.: already try to decrypt with many programs but doesn't works....
someone can help me please.... Here is :
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the file is encrypted this way: if you ignore first 4 bytes, group of 532 bytes is xor-ed with first byte of encryption key, next 532 bytes are xor-ed with second byte of key.. etc..
structure of the decrypted file is unknown to me, maybe someone will be lucky.
no clear coordinates can be seen..
here is the encryption key for decrypting the file:
byte enc_key = new...
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