Dice King analysed:)

[Ingwe]

yes i wasted some time working out all this (some most people were just too lazy to do) anyways i searched for this and it wasnt here so i thought id post.
Its colour coded too hehehehehehe. Anyways since i tried to copy and paste and that didnt work i think ill just attach a link.
All credit goes to me cause i spent an hour doing it out so neat and colour coded hehehehe.
its an Excel file so its all yours have fun
if you find this helpful karma would be nice

[hieitk]

wow this seem like a lot of work

using your table of chance I wanted to know what happen if you always play to number 10 or 11 the 216 times using the max bet (30k) and this is what i got:

cost = 216*30000=6.480.000
reward = 216*(12,5/100)*8*30000 = 6.480.000
profit = 0

-edit-
now that I think again is kinda logical because:
chance (%) = 100/(xN)

for example:
chance for number 5 = 100/36 = 2.78 the same as on your table =S

so now if we do
profit = NumOfGames*Bet - NumOfGames*(Chance/100)*(xN)*Bet
profit = NumOfGames*Bet*(1 - (Chance/100)*(xN))
profit = NumOfGames*Bet*(1 - 1)
profit = NumOfGames*Bet*0
profit = 0

[Matt.dk]

Whenever I feel like gambling, I just open 2 characters, pop 300k on each, and wipe the x216 options with 10k bets for 10 rounds. I usually get the 2.1mil, rarely I don't. Thats profit...

And btw, its "Analysed"...

[Ingwe]

Originally posted by Matt.dk+May 18 2007, 02:48--></span><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Matt.dk @ May 18 2007, 02:48)</td></tr><tr><td id='QUOTE'> Whenever I feel like gambling, I just open 2 characters, pop 300k on each, and wipe the x216 options with 10k bets for 10 rounds. I usually get the 2.1mil, rarely I don't. Thats profit...

And btw, its "Analysed"... [/b]

ya i kinda guessed it was that but i was really tired after it :/ i was debating to put the y in but meh the i seemed easier at the time ill fix it for you xD

<hr>Append on May 18 2007, 20:33<hr><!--QuoteBegin--hieitk@May 18 2007, 01:27
wow this seem like a lot of work

using your table of chance I wanted to know what happen if you always play to number 10 or 11 the 216 times using the max bet (30k) and this is what i got:

cost = 216*30000=6.480.000
reward = 216*(12,5/100)*8*30000 = 6.480.000
profit = 0

-edit-
now that I think again is kinda logical because:
chance (%) = 100/(xN)

for example:
chance for number 5 = 100/36 = 2.78 the same as on your table =S

so now if we do
profit = NumOfGames*Bet - NumOfGames*(Chance/100)*(xN)*Bet
profit = NumOfGames*Bet*(1 - (Chance/100)*(xN))
profit = NumOfGames*Bet*(1 - 1)
profit = NumOfGames*Bet*0
profit = 0 [/quote]
ive thought a bit about what you said but the likelyhood is that youll either make a profit or loss very unlikely to turn out the same as what you bet.

First of all the chance of you getting the right number has to be the same every single time the die are rolled. therefore (in theory) it is quite possible to get the same number 216 times in a row. i made the table out to basically show exactly which is more likely to be the right number in one role of the die.


anyways added in some more stuff you can now calculate your winnings

new link in first post

[Bepruotiz]

wow=] ill try ,thnx