[RELEASE] 9Dragons XSD Editor

[Adek]

Originally Posted by saweet

Done. Searches tables for rows matching the Name column. Find Next wraps around when it reaches the end. Find Next table search order can be altered by manually selecting a table.

Long time no see, saweet. Nice to see you again on ePvP's 9D section. You told it's easy to figure out the encryption keys. Can you tell - how?

By the way - thanks for great update.

[soly95]

Originally Posted by adek1994

Long time no see, saweet. Nice to see you again on ePvP's 9D section. You told it's easy to figure out the encryption keys. Can you tell - how?

By the way - thanks for great update.

US Cipher Keys is 17 & 08

KR Cipher Keys is 27 & 09

DE same as US

Dont know about VN yet

[Tenge500]

Saweet, you're a beast. I pressed thanks button.

[bog18dy]

Awesome!!! I have waited for this for a long time...

[dthik]

Originally Posted by soly95

US Cipher Keys is 17 & 08

KR Cipher Keys is 27 & 09

DE same as US

Dont know about VN yet

VN is: 07 & 11

[soly95]

Originally Posted by dthik

VN is: 07 & 11

imma downloading it now anyway ><

[witek1992]

Originally Posted by saweet

Done. Searches tables for rows matching the Name column. Find Next wraps around when it reaches the end. Find Next table search order can be altered by manually selecting a table.

Thank you very much it's hella easier now.

[saweet]

Thanks everyone for sharing keys.

Originally Posted by adek1994

Long time no see, saweet. Nice to see you again on ePvP's 9D section. You told it's easy to figure out the encryption keys. Can you tell - how?

By the way - thanks for great update.

The 2nd key is obvious because it's only used in 2 byte characters and only ever used in the 2nd byte position. They use XOR encryption so it becomes very obvious when null is XOR'd, because 0 XOR N = N. Thus N is the 2nd key.

The 1st key can be learned by knowing the most common character in a string, with that you can guess the possible keys. What I did was grab all the table names in both an unencrypted and an encrypted XSD and compared string length to find matches as possible candidates for the real value. MobModel_XMS was a good choice because we have 3 Ms in a single short string. With that I found ZxuZxsr{HOZD of the same string length in the encrypted file. Notice the pattern, 3 Zs in the same position?

If you know Z (5A) in a string is really M (4D), all we have to do is figure out what possible XORs of 4D will equal 5A to get a list of possible keys. I did this in python and had the key in a fraction of a second:

>>> [hex(i) for i in range(256) if 0x4d ^ i == 0x5a]
['0x17']

Lets see what happens (ciphertext is "ZxuZxsr{HOZD" in hex)

>>> ciphertext = bytearray([0x5A, 0x78, 0x75, 0x5A, 0x78, 0x73, 0x72, 0x7B, 0x48, 0x4F, 0x5A, 0x44])
>>> bytearray([ciphertext[i] ^ 0x17 for i in range(len(ciphertext))])
bytearray(b'MobModel_XMS')
>>>

Viola

[thai0101]

Originally Posted by saweet

Thanks everyone for sharing keys.



The 2nd key is obvious because it's only used in 2 byte characters and only ever used in the 2nd byte position. They use XOR encryption so it becomes very obvious when null is XOR'd, because 0 XOR N = N. Thus N is the 2nd key.

The 1st key can be learned by knowing the most common character in a string, with that you can guess the possible keys. What I did was grab all the table names in both an unencrypted and an encrypted XSD and compared string length to find matches as possible candidates for the real value. MobModel_XMS was a good choice because we have 3 Ms in a single short string. With that I found ZxuZxsr{HOZD of the same string length in the encrypted file. Notice the pattern, 3 Zs in the same position?

If you know Z (5A) in a string is really M (4D), all we have to do is figure out what possible XORs of 4D will equal 5A to get a list of possible keys. I did this in python and had the key in a fraction of a second:

>>> [hex(i) for i in range(256) if 0x4d ^ i == 0x5a]
['0x17']

Lets see what happens (ciphertext is "ZxuZxsr{HOZD" in hex)

>>> ciphertext = bytearray([0x5A, 0x78, 0x75, 0x5A, 0x78, 0x73, 0x72, 0x7B, 0x48, 0x4F, 0x5A, 0x44])
>>> bytearray([ciphertext[i] ^ 0x17 for i in range(len(ciphertext))])
bytearray(b'MobModel_XMS')
>>>

Viola

greate work brb ... but can you explain how to program that 2 cipher XOR encrytion ?

it's working great !

[Adek]

Originally Posted by thai0101

greate work brb ... but can you explain how to program that 2 cipher XOR encrytion ?

it's working great !

Wow, great job. That's the one from Rage Zone? Or VN one?

[soly95]

Originally Posted by adek1994

Wow, great job. That's the one from Rage Zone? Or VN one?

VN .

Arale

[thai0101]

Originally Posted by adek1994

Wow, great job. That's the one from Rage Zone? Or VN one?

well that's CuuLongViet... handling 9D for Vietnamese

Originally Posted by soly95

VN .

Arale

---> VN . ---> Yes

---> Arale ---> No (scum bag one)

[witek1992]

Any idea how to translate 9D RU? When I open file it says it has no encryption...
When I click on Save As I get ZsutsuuHGzusuoOo etc.

I tried to save it with and without encryption, I tried to get my old XSD non ecrypted and put inside but i get ZsutsuuHGzusuoOo...

[saweet]

Originally Posted by witek1992

Any idea how to translate 9D RU? When I open file it says it has no encryption...

Can you upload the XSD so I can take a look?

[witek1992]

Originally Posted by saweet

Can you upload the XSD so I can take a look?

Here it is:


thanks for looking at it.