[HELP]About Making Hacks ~

[branj13]

why? does the kom file nowadays checks ALL algorithms like md5 etc?

[sOulimperfect]

to prevent file modification.

[branj13]

oh my... bruting all algorithms is going to be a huge pain in the neck... they made it almost fool-proof this time

[MiniMango]

if this helps, there is online MD5 decrypter

[noein8413]

@all

here is a tip on how to make a v4 compiler

if you are familiar with this one "0xb290207"..... you just need to encrypt it back.. hope it helps

[sOulimperfect]

@noein all i can say is thats hexadecimal. it could be anything from checksum to addresses

[noein8413]

@soul

its not hexadecimal (in hex there is no "x") .. if you back read sir makim's post in the gchc you will know what i mean..

[sOulimperfect]

of course there is no x in hexadecimal

the symbol = 0x simbolizes that the next numbers are hexadecimal or such an abrevation

making b290207 hexadecimal, but its missing one digit

probably a zero at the end B290207 when converted to decimal becomes 2995789936

29 95 78 99 36

a perfect sequence for ASCII code (LOL i love ASCII)

29 95 78 99 36 = ^_Nc$

which makes no sense at all

is it me? or am i keep on comparing number to ASCII? ._. ohh boy....

-EDIT-
i just read it
there is a zero just before the everything else

0x0B290207

this cannot be converted to ASCII. its either an address in memory since the address are also represented as hexadecimal but it doesn't look like it, cause all the numbers are far from being memory.
or maybe it does not mean anything at all.

[noein8413]

this ASCII code "0xb290207" is the reason why we can extract the v4 kom files...

[deleted]ooppsss.. sorry i got carried away and posted my v4 compiler code XD

have you noticed that the v. 4 has only key in it.. unlike the previous version... so my hypothesis .. is if we can decrypt it.. why dont we use the key to encrypt it again after we compile it.. (im not good at encryption... pardon me if some of my explanations are wrong)

[sOulimperfect]

no no. thats not ascii pardon my obsession with ascii, its more like a key, yes i think that is possible.

but whatever that means, im sure there could be a relation with that and this "0x34" found on the 3rd line.

or maybe it is the key itself and does not do anything at all.

--edit--

yes, v4 has this KEY part in its compression.

what if this key, is a method?

something like this:

def _init_(self, name, compressed_size, decompressed_size, file_time, offset, KEY)

--EDIT--

that was your v4 compiler code? -____- or was it aluigi's?

[~Blaze]

i have a question soul ~

loooooong ago in epvpers i saw a tutorial ... the very first hack to be made for GC
its not sudden death but its a friendly mob you can simply make it work by just editing
one thing in the kom file ... but i seem to forgot what to edit, it doesnt need a bypass
as far as i can remember ..

will it work in our GC today ??

friendly mobs can still be a useful hack, somewhat a replacement while waiting
for SD hacks ~

[sOulimperfect]

yes it will get detected, because even if there is the slightest change of content in a file its checksum will change greatly.

[darkheaven09]

@soul
sir, i have a question... what does "struct.pack" means???...

[sOulimperfect]

i bet thats python, struct is defined in python already like print, raw_input etc and pack is a method, notice that they are separated by a dot. struct.method i have 0 background in structures even in C, but i think its identical with a function and a class. just a theory tho. im still a week studying python so im no pro.

[darkheaven09]

du u think sir, editing python file can possibly make a v4 compiler??.. i dunno sir where do i start creating v4 compiler...