[Question] about Packets .

[romeoromeo]

what i know about conquer packets is . the last 8 byts are seal .
and the first two bytes for Length and the next two byts for header
but this packet is confusing me !!! can anybody help ?

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

hope somone will answer this

[Zeroxelli]

Without even converting the hex, I can tell you right now, that packet is encrypted.

[Spirited]

You could try my tutorial. I don't know how good of a job I did on it though:

[Zeroxelli]

Originally Posted by Fаng

You could try my tutorial. I don't know how good of a job I did on it though:

Took a quick look at it, looks to be pretty helpful to me.

[romeoromeo]

if the packet is encrypted ...... how to dencrype it ? !!! tips ?

[Spirited]

Originally Posted by romeoromeo

if the packet is encrypted ...... how to dencrype it ? !!! tips ?

Why is it encrypted in the first place?

[Zeroxelli]

Probably wasn't decrypted at the time of logging.

[romeoromeo]

Originally Posted by Fаng

Why is it encrypted in the first place?

im not sure if i understand your question right or ....
but i think you mean the packet was encrypted at first place so no body can dencrypted it . ... ?
anyway .... i do not think it was encrypted and that is why i made this thread .
because Synsia sand : "You can use this program to study and analyze packets (non-encrypted) on the latest CO client." in this thread


and i read your threat toutorial about two times, and i mention few things in here too
if the packet is not encrpted and ... first 2byte for length and 2nd two byts for header and last 8 bytes for seal ..... so this packet is confusing me

[Zeroxelli]

Originally Posted by romeoromeo

im not sure if i understand your question right or ....
but i think you mean the packet was encrypted at first place so no body can dencrypted it . ... ?
anyway .... i do not think it was encrypted and that is why i made this thread .
because Synsia sand : "You can use this program to study and analyze packets (non-encrypted) on the latest CO client." in this thread


and i read your threat toutorial about two times, and i mention few things in here too
if the packet is not encrpted and ... first 2byte for length and 2nd two byts for header and last 8 bytes for seal ..... so this packet is confusing me

I'm looking at the 2-byte blocks of data, and the hex is too large and too constant to have been decrypted, so I don't even have to bother converting it to ASCII. You're trying to log packets without the necessary key to pass to your decryption function for the newer clients, and thus, you're not decrypting them at all. And the problem with that is, instead of leaving them intact, you're more likely than not trying to decrypt them with an incorrect key, which just turns them into a pile of garbage.