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In one script the 1. form hidden and the 2. show

Discussion on In one script the 1. form hidden and the 2. show within the AutoIt forum part of the Coders Den category.

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Old   #1
 
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In one script the 1. form hidden and the 2. show

#thanks
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Old 11/12/2013, 19:53   #2
 
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Old 11/12/2013, 20:01   #3
 
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Code:
$Form1 = GUICreate("", 117, 64, 632, 308)
$Label1 = GUICtrlCreateLabel("Second Gui", 24, 8, 60, 17)
$Button1 = GUICtrlCreateButton("Start", 8, 32, 97, 25)

$Form2 = GUICreate("", 143, 56, 654, 282)
$Button2 = GUICtrlCreateButton("Hide / Show", 8, 8, 129, 41)
GUISetState(@SW_SHOW)

While 1
    $nMsg = GUIGetMsg()
    Switch $nMsg
        Case -3
            Exit

	Case $Button1
		GUISetState(@SW_HIDE, $Form1)
		GUISetState(@SW_SHOW, $Form2)

	Case $Button2
		GUISetState(@SW_HIDE, $Form2)
		GUISetState(@SW_SHOW, $Form1)

    EndSwitch
WEnd
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Old 11/12/2013, 20:17   #4
 
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du must aufpassen das du nicht in eine andere While Schleife gehst..bzw. herstellen ..das kann böse enden :b
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Old 11/12/2013, 20:22   #5
 
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Das ist schon so in Ordnung man könnte auch noch
Code:
Opt("GUIOnEventMode")
verwenden aber dann kann man die Schleife weglassen, sofern das kein aufwendiges Programm wird geht das meiner Meinung nach.
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Old 11/12/2013, 20:28   #6
 
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Quote:
Originally Posted by alpines View Post
Das ist schon so in Ordnung man könnte auch noch
Code:
Opt("GUIOnEventMode")
verwenden aber dann kann man die Schleife weglassen, sofern das kein aufwendiges Programm wird geht das meiner Meinung nach.
ich weiß :b mach ich immer :3 aber ich hab sein source gesehn btw. deinen x) habs mir so gedacht
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