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Warrock login string

Discussion on Warrock login string within the WarRock forum part of the Shooter category.

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Old   #1
 
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Warrock login string

With my program I login to the warrock server. I get my NPP through webrequest when I first login.

I build my string like this:

Code:
            sb.Append(Environment.TickCount.ToString());
            sb.Append(" 4352 ");
            sb.Append(WRCrypt.rnd());
            sb.Append(" 0 ");
            sb.Append(username);
            sb.Append(" ");
            sb.Append(npp.Split(':')[3]);
            sb.Append(" ");
            sb.Append(username);
            sb.Append(" ???? 1 0 ");
            sb.Append(npp);
            sb.Append(" ");
            sb.Append(Environment.NewLine);
            byte[] bBytes = Encoding.ASCII.GetBytes(sb.ToString());
            bBytes = WRCrypt.xor(bBytes, (byte)195);
            return bBytes;
First time I login and everything works fine. Second I login with different account and retreives NPP and my first account logs in?

Somebody Knows what the error is?
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Old 01/12/2014, 15:59   #2
 
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Try to add another webbrowser
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Old 01/12/2014, 16:20   #3


 
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U ever heard of "Logout"? U can't login a second time within the same session -.-
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Old 01/12/2014, 16:32   #4
 
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Send logout
Close Socket
Wait 1 sec
Relogin

Have fun
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Old 01/12/2014, 17:11   #5
 
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Aaah, So when I don't send the logout packet my account stays in the server right?
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Old 01/13/2014, 16:25   #6
 
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Yes and is timegettime not environment.tickcount
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Old 01/13/2014, 19:11   #7



 
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Quote:
Environment.TickCount Property
Gets the number of milliseconds elapsed since the system started.
Quote:
timeGetTime function
The timeGetTime function retrieves the system time, in milliseconds. The system time is the time elapsed since Windows was started.
They are the same.
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Old 01/13/2014, 19:54   #8
 
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The system time does not even matter. Technically, the timestamps only need to follow the basic rules of linear temporal logic (LTL): For every packet a and b where a gets sent before b the timestamp of a needs to be smaller than the timestamp of b. Therefore you might as well just add one to the any packets timestamp to receive the next timestamp.
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