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[Lelees!]Steeds Walk

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Old 05/02/2011, 23:05   #31
 
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Quote:
Originally Posted by thesamuraivega View Post
why? i have problem in this...
if (Client.ActiveStats.ContainsKey(Enum.Effect.Riding))
cus it has to be ActiveStats1.ContainsKey(Enum.Effect.Riding)) if you are using the hellmouth source (as far as i know)


Quote:
Originally Posted by Spirited View Post
*sigh* ok, all of this trolling on me has been because people think that I can't code...
well fine. I'll release steed walking... the real one... but **** you guys... now I understand what KraHen has been saying... it's just constructive crit. Let's chill out.
too late Mr` smart azz you were crying about it last night and now after its released you wanna talk **** and act like(at least you know what you are talking about) pfff please just please (GTFO) and dont make me say anything bad ........lmao



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Old 05/02/2011, 23:20   #32
 
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Quote:
Originally Posted by { Angelius } View Post
cus it has to be ActiveStats1.ContainsKey(Enum.Effect.Riding)) if you are using the hellmouth source (as far as i know)




too late Mr` smart azz you were crying about it last night and now after its released you wanna talk **** and act like(at least you know what you are talking about) pfff please just please (GTFO) and dont make me say anything bad ........lmao
hey how i can fix the skill for the steeds


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Old 05/02/2011, 23:37   #33
 
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Quote:
Originally Posted by thesamuraivega View Post
hey how i can fix the skill for the steeds
find
Quote:
public enum Skills : uint
{
and right under that or it doesent matter it has to be in the side the enum Brackets add this (Ride = 7001,)

in client.cs add this
Quote:
public bool Riding = false;
in magic.cs

Quote:
case Enum.Skills.Ride:
{
if (Client.Riding)
{
Client.Riding = false;
Client.RemoveEffect1(Enum.Effect.Riding);
// send the vigors and whatever
}
else
{
Client.Riding = true;
Client.AddEffect1(Enum.Effect.Riding, 0, false);
//and send the skill use packet here
}
}
learn the skill and use it :P

that was just what i could think off atm but its not the best way to handle it :P its just to test the steed walk ha ha
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Old 05/02/2011, 23:43   #34
 
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Chill the **** out dude.

Look at my post, I said "I never tested it" but it looked like it would work without errors(which the code itself would) not what the code is suppost to do but even now, %8 doesnt look right, but I maybe wrong.

Also a more organized way to check if the client is mounted do something like "if (client.StatusFlags.Contains(StatusFlags.Riding))" makes more sense doesnt it?


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Old 05/02/2011, 23:50   #35
 
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Originally Posted by _DreadNought_ View Post
Chill the **** out dude.

Look at my post, I said "I never tested it" but it looked like it would work without errors(which the code itself would) not what the code is suppost to do but even now, %8 doesnt look right, but I maybe wrong.

Also a more organized way to check if the client is mounted do something like "if (client.StatusFlags.Contains(StatusFlags.Riding))" makes more sense doesnt it?
maybe but believe me i this thread was just a trolls hunting ha ha =))
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Old 05/03/2011, 00:34   #36
 
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Quote:
Originally Posted by { Angelius } View Post
maybe but believe me i this thread was just a trolls hunting ha ha =))
hey bro you can add me pliz



ty
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Old 05/03/2011, 00:50   #37
 
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The code is ... not working good. I tested the code myself and it doesn't work.

There is a total of 32 directions now, 8 basic ones + 24 slides.
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Old 05/03/2011, 00:56   #38
 
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Originally Posted by -impulse- View Post
The code is ... not working good. I tested the code myself and it doesn't work.

There is a total of 32 directions now, 8 basic ones + 24 slides.
change the (Byte Dir = Data[4]) to (Byte Dir = Data[4] % 8) but when you send the walk packet send the dir as(Data[4]) not (Data[4] % 8) and thats it i already changed it up there and i dear anybody that says its not working :S
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Old 05/03/2011, 01:11   #39
 
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Quote:
Originally Posted by { Angelius } View Post
change the (Byte Dir = Data[4]) to (Byte Dir = Data[4] % 8) but when you send the walk packet send the dir as(Data[4]) not (Data[4] % 8) and thats it i already changed it up there and i dear anybody that says its not working :S
impulse is right. there are 32.
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Old 05/03/2011, 01:16   #40
 
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Originally Posted by Spirited View Post
impulse is right. there are 32.
so as long as that is correct than (Can YOU figure what is missing in that code !!)i doubt it !!
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Old 05/03/2011, 01:19   #41
 
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Quote:
Originally Posted by { Angelius } View Post
change the (Byte Dir = Data[4]) to (Byte Dir = Data[4] % 8) but when you send the walk packet send the dir as(Data[4]) not (Data[4] % 8) and thats it i already changed it up there and i dear anybody that says its not working :S
it won't fix anything...nothing at all lol
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Old 05/03/2011, 01:27   #42
 
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ohh i'll be uploading something that uses the same code i posted here (testing thought) and well see

Edit: i cant Believe that You were the one that said it :P

and to be honest i went to sleep last night and im hoping that (you/pro4never) well not f**k up my day by telling them whats missing (and waste my chance to laugh at some of the stupid comments) lol but i guess i was wrong

for the its not working ppl!!!
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Old 05/03/2011, 06:46   #43
 
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No Fang.. Noone wants you here I hope you're still discouraged to start coding again..
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Old 05/03/2011, 10:22   #44
 
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Quote:
Originally Posted by { Angelius } View Post
ohh i'll be uploading something that uses the same code i posted here (testing thought) and well see

Edit: i cant Believe that You were the one that said it :P

and to be honest i went to sleep last night and im hoping that (you/pro4never) well not f**k up my day by telling them whats missing (and waste my chance to laugh at some of the stupid comments) lol but i guess i was wrong

for the its not working ppl!!!
You know, I am not a retarded guy and I can think on my own. I did see that there was the modulo 8 missing and I added it and it still didn't work.
Also, you're using useless switches just because they are easy to use.
SteedWalk1 is an useless variable.
Accessing a vector to get the add x, y is much more faster than this.

You have checks that are always true, and you can't understand that if move type is 0 you are walking normally riding or not.
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Old 05/03/2011, 10:41   #45
 
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Come on Angelius... can't you post ONE single post without using abusive language. You sound like a little child. Did you expect everyone would for you when you posted this? This forum is also for criticism.


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