Got bored one night, decided go make an equation on how to find how many "+1's" are needed to ... well "+" up an item. Took about an hour, with trial and error, but I came up with an equation.
This is to "+" up a "+0" item:
((3^x)/3)+1
x is equal to the "+#" desired. For example, if you wanted your "+0" item to be "+9," you plug 9 in where x is at.
((3^x)/3)+1
((3^9)/3)+1
(19683/3)+1
6561+1
6562
So, 6562 "+1" items are needed to "+9" a "+0" item.
If the item you wish to "+" is already a "+1" and a "+1" ONLY, then remove the +1 at the end of the equation ((3^x)/3)+1 so that you end up with ((3^x)/3).
Hope this helps you figure out how far you wanna go with your "+'ing!"
~Bosi~