Packet 1033 (Date/Time).

How can I show the current time of the host and I know it's Packet 1033.

Code:

MSG_DATE_TIME = 1033

Now, I cannot handle this complicated calculation or at least force it to read the real date and time of the host.

Here's the code:

Code:

public unsafe struct ServerTimePacket
    {
        public DateTime Time;

        public static ServerTimePacket Create()
        {
            var packet = new ServerTimePacket
            {
                Time = DateTime.UtcNow
                    .AddHours(Constants.TIME_ADJUST_HOUR)
                    .AddMinutes(Constants.TIME_ADJUST_MIN)
                    .AddSeconds(Constants.TIME_ADJUST_SEC)
            };
            return packet;
        }

        public static implicit operator byte[](ServerTimePacket packet)
        {
            var buffer = new byte[36 + 8];
            fixed (byte* ptr = buffer)
            {
                PacketBuilder.AppendHeader(ptr, buffer.Length, Constants.MSG_DATE_TIME);
                *((int*)(ptr + 8)) = packet.Time.Year - 1900;
                *((int*)(ptr + 12)) = packet.Time.Month - 1;
                *((int*)(ptr + 16)) = packet.Time.DayOfYear;
                *((int*)(ptr + 20)) = packet.Time.Day;
                *((int*)(ptr + 24)) = packet.Time.Hour;
                *((int*)(ptr + 28)) = packet.Time.Minute;
                *((int*)(ptr + 32)) = packet.Time.Second;
            }
            return buffer;
        }
    }

Please, I cannot open discussions about the author or anything related to the base.
Note, I have someone who are coding for me but he is busy at the moment so I decided to get a free help if there is anyone who can.