Hello, did anyone figured out how delay between walk packets is calculated. My approximation is something like 920/4 * length of previous step, but it's not enough. Weird thing is that delay is varying even thought step length is not changing.
How is the time delay between walk packets being calculated?
03/14/2019 19:07
lemon250#1
03/15/2019 12:40
GGGGame#2
_movetime = ServerManager.RandomNumber(400, 3200);
03/15/2019 17:12
FI0w#3
What a shiitQuote:
_movetime = ServerManager.RandomNumber(400, 3200);
its the Time for OpenNos to Move the Monsters....
03/15/2019 18:35
Nortank#4
Funny, I was looking for this two days ago. I did a :
std::ceil(speed/4)
but I think that is not that. (Got some buggy movespeed)
std::ceil(speed/4)
but I think that is not that. (Got some buggy movespeed)
03/16/2019 14:14
lemon250#5
After many tries i looked up at NosWings server source code, made a little change to monster movement delay equation and ended up with stepDelay = stepSize / (speed / 2.0f) * 1250. I don't have any idea if it's similar to what client does, but it works :D
03/18/2019 01:14
jinsun#6
Hi Flow I need talk You please add Discord Jes#8034Quote:
its the Time for OpenNos to Move the Monsters....
03/18/2019 03:51
0Lucifer0#7
Distance*2500/speed = timeofwalk
03/18/2019 12:55
Nortank#8
As an example :
My character got a movementspeed of 23.
(x;y) are my coordonate. If I go straight ahead, (x+8;y), (x-8;y), (x;y+8), (x;y-8) are all the possibilities. 8 is the traveled distance in a straight line.
If I am running diagonally, my possibilities are (x±6;y±6). What is my distance here ? 12 ? So the timing will be lower than before ?
=> Straight line : 8*2500/23 = 869
=> Diagonally : 12*2500/23 = 1300 ? I guess this is too large. Maybe 1300/2 = 650 ? Or sqrt(12)*2500/23 = 376. Guess that is too short.
Clientside, what is the way to get the distance ? (Currently I am using a fixe distance of 4)
My character got a movementspeed of 23.
(x;y) are my coordonate. If I go straight ahead, (x+8;y), (x-8;y), (x;y+8), (x;y-8) are all the possibilities. 8 is the traveled distance in a straight line.
If I am running diagonally, my possibilities are (x±6;y±6). What is my distance here ? 12 ? So the timing will be lower than before ?
=> Straight line : 8*2500/23 = 869
=> Diagonally : 12*2500/23 = 1300 ? I guess this is too large. Maybe 1300/2 = 650 ? Or sqrt(12)*2500/23 = 376. Guess that is too short.
Clientside, what is the way to get the distance ? (Currently I am using a fixe distance of 4)
03/18/2019 20:05
0Lucifer0#9
public static double Octile(int iDx, int iDy)
{
int min = Math.Min(iDx, iDy);
int max = Math.Max(iDx, iDy);
return min * SQRT_2 + max - min;
}
With iDx the diff in x and IDy the diff in y
Note: you can use any math distance formula
{
int min = Math.Min(iDx, iDy);
int max = Math.Max(iDx, iDy);
return min * SQRT_2 + max - min;
}
With iDx the diff in x and IDy the diff in y
Note: you can use any math distance formula