CO Packet hacking, and suite

Quote:

The 1st 4 bytes of the 1st key (vice versa, originally: 9D 90 83 8A): 8A 83 90 9D With the result of 3.): 00 FC E4 F7 The result: 8A 7F 74 6A The result must also be rated the other way round. Thus, the first four bytes of the key now are: 6A 74 7F 8A Repeat that until you converted the complete 1st key.

Do you then goto the Next for bytes or the second byte in the key?


I have built a program wich works keys 3 and 4 out for you :) i just need to confirm this 1 thing then i will release it

awesome :D

omg that was 1 wick reply :D i just need ultima to answer my question and them i will release it

I think you should pm him :p

ok, when i release this will it be pinned?

Lowfyr, didnt u work out the encryption?

Quote:

Originally posted by ultimatehaker@May 12 2005, 11:17 ok, when i release this will it be pinned?

sure

Quote:

Lowfyr, didnt u work out the encryption?

no, I just translated the guide with noir, but it was created by a epvp member

yay, ok i just need to get in contact with this member, i will release a version up here now, i just hope it all works fine!

woooo..wowx wad will the hack do? :D

Basically This Program Does All OF THis For You:

Quote:

The key in the incoming package is the 11th + 10th + 9th + 8th byte from startup. In this example: 20 5C 48 F4 The 2nd key is the 7th + 6th + 5th + 4th byte in the package. In this example: 00 44 A6 2E And now, to get the 3rd and 4th key, you need to do this: 1.) Add key 1 with key 2 205C48F4 + 0044A62E = 20A0EF22 2.) XOR result of 1.) with 4321 XOR 20A0EF22, 4321 = 20A0AC03 3.) XOR Key 1 with result of 2.) XOR 205C48F4, 20A0AC03 = 00FCE4F7 4.) IMUL result 3.) with result 3.) IMUL FCE4F7, FCE4F7 = F9D39310E651 (logical multiplication // result is only 4 byte long -> 9310E651) And now, to create the 3rd and 4th key correctly, you need to do this: Always use the first 4 bytes of the 1st key with the result of 3.) and produce it with XOR: The 1st 4 bytes of the 1st key (vice versa, originally: 9D 90 83 8A): 8A 83 90 9D With the result of 3.): 00 FC E4 F7 The result: 8A 7F 74 6A The result must also be rated the other way round. Thus, the first four bytes of the key now are: 6A 74 7F 8A Repeat that until you converted the complete 1st key. The 2nd key has to be converted the same way, but with the difference that you need to use the result of 4.), not 3.). The 1st 4 bytes of the 2nd key (vice versa, originally: 62 4F E8 15): 15 E8 4F 62 With the result of 4.): 93 10 E6 51 The result: 86 F8 A9 33 The result must also be rated the other way round. Thus, the first four bytes of the key now are: 33 A9 F8 86 Now you have the 3rd and 4th key you need to have to send packages.

Enjoy :)

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so ur done? plz make a new topic with your tool

it will be pinned

and how to find the packet you need?

btw nice job !

use, wpe its normally the first packet u recieve from the server!

omg u made it hehe ^^

o!! super nice job!! :D:D:D btw wad we do wif those? :S
karma for u!