x y angle calculation [question]

Hey guys,

I'd like to ask something about a calculation which I was thinking of.

I got 2 points, 1 point is the point where I am and the other point is the point to which I want to move. But first I have to look towards this point ( face angle ). It is about a game, called warhammer.

I heared, that there is a possibility to calculate the angle.

Let's say the point is (which I was reading out CE):
x1 = 27802.375;
y1 = 17086.75;
x2 = 27520;
y2 = 18296.4375;

I know how to calculate the distance between two points, it must be something like.

X = x2 - x1;
Y = y2 - y1;
Distance = Math.sqrt(pow(X, 2) + pow(Y, 2));

Angle:
Angle = Math.Acos(-Y, Distance) / 6.28 * 360;

But I'm not sure and maybe someone has another solution to find out the face angle


best regards

What you have is fine, but you could cut out the distance caclucation by using Atan(X, Y). I assume you need the distance for other calculations though anyway.

oh yes... you're right... Thanks!

This is my function and it works perfectly.

public double angle(double x1, double y1, double x2, double y2)
{
double X = x1 - x2;
double Y = y1 - y2;

double distance = Math.Sqrt(Math.Pow(X, 2) + Math.Pow(Y, 2));
// double result = Math.Acos(-Y / distance) / 6.28 * 360;
double result = Math.Atan(X / Y) / 6.28 * 360;
if (result < 0) result = result * -1;

return result;
}