To Share or Not to Share

04/16/2008 06:07 iluvreggie09#316
ohh.. i managed to get the first packet.. its the correct one.. i tried it but now i dont know what packet should i send to make it +1 - +4

14 crashes the game.. dunno why.. maybe i should use gems
04/16/2008 06:09 lulusuper#317
anyone has a private server at home? ican help u guys.but not the code..:)
04/16/2008 06:12 Altec2#318
Can smbd separe the 33 bytes packet in 8 corect lines(tiers)?
In the evening i will post the result...
04/16/2008 06:17 iluvreggie09#319
NOW I KNOW WHAT ZHOEA IS TALKING ABOUT... 8 PACKETS TO BE CHANGED
EVERY UPGRADE DIFF PACKET.. :)
04/16/2008 06:25 kai025#320
^

mind sharing sir??
04/16/2008 06:29 greedlt#321
iluvregie09 ur right and yes its easy u just need common knolege/sense and it only took me an hour and a half lol 3 things u need to figure this out is
1.common sense*IQ of 110 ^_~
2.patience*i have very little but had just enough*
and
3.u need to listen carefully...
04/16/2008 06:32 MissRoadkill#322
!.! no private sever for me :(!!!!! fudge back to officail
04/16/2008 06:38 greedlt#323
Quote:
Originally Posted by MissRoadkill View Post
!.! no private sever for me :(!!!!! fudge back to officail
y dont u just join a server official ones r too slow ._.
04/16/2008 06:39 iluvreggie09#324
whats the max upgrading chance?? just give me a clue.. i multiplied it all over and over but still cant get it right.. but i know where the success rate is located :)
04/16/2008 06:45 MissRoadkill#325
what reggie said!!
04/16/2008 06:55 iluvreggie09#326
huh?? :confused:

btw, im still working on the sucess rate.. dunno if its really 14. cuz it cracked my upgrade
04/16/2008 07:17 HAPPYMEAL08#327
Does anyone know the right value for 100% success rate? this is the same question as rejjie's.
04/16/2008 08:01 iluvreggie09#328
as what zhoea said.. packets changed every upgrade you have to sniff..
04/16/2008 08:07 chowking202#329
hey where is the succes packet?????:confused:
04/16/2008 08:13 klopina#330
Peoples :) Lets try with t2 (there are many gems)... and will write our results o+1 on+2 on+3 on+4 ... maybe we are solve this problem :)))