packets after auth response

'02 94 E0 71 76 59 40 60 C5 16 AA B3 84 50 6D F9
40 91 27 82 0B D7 E7 79 C4 16 AD BF 84 55 68 F2
44 9E 2A 33 02 D5 E2 72 C3 10 A0 60 82 5A 63 FB
4E 92 2D 39 C8 D1 2C 3B 80 9A 0F B1 29 5F 6E F4
6A CE 17 D7 46 C0 AF 74 C1 1A A6 B2 80 54 69 FD'

Is this how you send the packet? Well That's wrong.
That's how the packet is received from TQ, Now make a structure from it.

Quote:

Originally Posted by iStefan '02 94 E0 71 76 59 40 60 C5 16 AA B3 84 50 6D F9 40 91 27 82 0B D7 E7 79 C4 16 AD BF 84 55 68 F2 44 9E 2A 33 02 D5 E2 72 C3 10 A0 60 82 5A 63 FB 4E 92 2D 39 C8 D1 2C 3B 80 9A 0F B1 29 5F 6E F4 6A CE 17 D7 46 C0 AF 74 C1 1A A6 B2 80 54 69 FD' Is this how you send the packet? Well That's wrong. That's how the packet is received from TQ, Now make a structure from it.

Not sure what you mean.

Quote:

Originally Posted by iStefan '02 94 E0 71 76 59 40 60 C5 16 AA B3 84 50 6D F9 40 91 27 82 0B D7 E7 79 C4 16 AD BF 84 55 68 F2 44 9E 2A 33 02 D5 E2 72 C3 10 A0 60 82 5A 63 FB 4E 92 2D 39 C8 D1 2C 3B 80 9A 0F B1 29 5F 6E F4 6A CE 17 D7 46 C0 AF 74 C1 1A A6 B2 80 54 69 FD' Is this how you send the packet? Well That's wrong. That's how the packet is received from TQ, Now make a structure from it.

No ! I`m just only printing buffer as hex values. Its easyer to read it for your eyes. Sending and receiving then in byte[] buffer !!!